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Apparently, the Ruskies keep a loaded firearm in their little spaceship. While I doubt there's much of a need for one up there, I don't begrudge them for having it. However, guns and Zero-G don't make a lot of sense for me.

Here on Earth, I use the friction generated by my feet against the ground (which are held together via gravity) to stay in one place when I shoot. The amount of force pushing against my body is not enough to overcome the friction of my soles.

In space, if you shot a gun, wouldn't you also go back at a few hundred feet per second?

Or do I need to brush up on my physics again?

rolled out on Thursday, February 14, 2008 1:46 PM
Comments
# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/14/2008 2:12 PM

Brush up on your physics. Shooting a gun would propel you backwards, but not by much as the bullet would have to overcome your inertia. If somehow you were able to direct all of the energy of the bullet into you, you might get moving a little bit more.

Remember, the equation is m1v1 = m2v2, or mass x velocity of the first object will equal the mass x velocity of the second.

So a .45 (13 grams) leaves the barrel at 290 m/s so 0.013*290 = 3.77kg.m/s.
A man weighs 85 kg, so 3.77 / 85 = 0.044 m/s of velocity imparted to you

# re: How would this work exactly? - DM

Rolled Out On: 2/14/2008 2:13 PM

You would be pushed back, however not that fast. You must take into account the mass of the bullet vs. the mass of your body+gun.

# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/14/2008 2:17 PM

keep in mind if a bullet had the energy to accelerate you to a few hundred feet per second, it would do so INSTANTLY (or at least as fast as the bullet accelerates). That much energy means that shooting a gun at the range would likely break your arms.

# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/14/2008 2:18 PM

Which is also why bullet impacts don't send people flying, despite the best attempts at Hollywood to demonstrate otherwise

# re: How would this work exactly? - Gregory Morris

Rolled Out On: 2/14/2008 2:20 PM

And, uh, you'd put a hole in the tiny tincan you are living in, which quite frankly could be worse than anything the gun might be used against. Unless they have special "space bullets". If they do, I want some.

# re: How would this work exactly? - mgroves

Rolled Out On: 2/14/2008 2:28 PM

Didn't you see Moonraker? C'mon!

# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/14/2008 2:40 PM

Greg,
Frangible rounds would likely be OK in the ISS, as it has to withstand micro-meteor impacts. And the ISS has repair kits to fix leaks, so while I would hardly recommend casually shooting a handgun up there, one errant round is unlikely to cause explosive decompression (unless it smacks some kind of airlock control, but methinks that is more Hollywood type incidence).

# re: How would this work exactly? - BobG

Rolled Out On: 2/14/2008 2:42 PM

I'd worry more about the bullet bouncing around and hitting something important----like me.

# re: How would this work exactly? - Robb Allen

Rolled Out On: 2/14/2008 3:15 PM

Dammit, I wrote that wrong. I know you wouldn't go back in the hundreds of feet per second, I meant to say wouldn't the X foot pounds at Y FPS have a rather large effect on you?

When I shoot, it's enough to push my arms up. I wondered in 0G if that would translate into a nice little shove.

# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/14/2008 3:23 PM

As I showed up above, you'd get pushed back 0.044 m/s, or .144357 ft/sec, or 0.1 mph.

It ain't much, but if you had a mini-gun and 10000 rounds of ammo, I bet you could get moving at a pretty good clip.

# re: How would this work exactly? - Robb Allen

Rolled Out On: 2/14/2008 3:32 PM

My Off the Top of the Head calculations were basically "Lessee... 800 foot pounds muzzle velocity, 200 pound guy, 800/200 = 4. So 4 something."

# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/14/2008 4:11 PM

Robb,

You are confusing energy and momentum. A .45 ACP round leaves the barrel with about 370 ft-lbf (foot-pound force) of kinetic energy, but only 3.77 kg-m/s of momentum.

Kinetic Energy = 1/2 x mass x velocity x velocity

Momentum = mass x velocity

Make sense, or do I need to give a full lesson on kinematics?

# re: How would this work exactly? - straightarrow

Rolled Out On: 2/14/2008 6:44 PM

kinetics? Wasn't that invented by L. Ron Hubbard?

# re: How would this work exactly? - straightarrow

Rolled Out On: 2/14/2008 6:58 PM

Rob I put that comment on the wrong post, could I get you to move it to the post about gunlocks?

# re: How would this work exactly? - Billll

Rolled Out On: 2/14/2008 8:16 PM

I understand the gun is a holdover from the Russkie space program. They land their astronauts on land, in Siberia, and getting to the landing site is not as easy as the ocean-based landings the US used, pre-shuttle. The gun is a survival tool for an astronaut lost in the Siberian woods.

There is a scene in the book "Ragamuffin" in which a minigun is used as a propulsive device, and a submachine gun is used for steering control.

# re: How would this work exactly? - Justin Buist

Rolled Out On: 2/14/2008 11:41 PM


The gun is a survival tool for an astronaut lost in the Siberian woods


I was going to point that out but you beat me to it.

# re: How would this work exactly? - MadRocketScientist

Rolled Out On: 2/16/2008 11:50 AM

Very funny straightarrow, don't be confusing Kinematics with dianetics. One is science, the other is woo.

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